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# Could someone help me with some math?

## 1. Three boxes, A, B, C, had 260 ping pong balls. Lisa added some ping pong balls into box and the number of ping pong balls tripled. She took out half of the ping pong balls in box B and added 40 to box C. The ratio of the number of ping pong balls in boxes A, B, C became 6:4:5. Find the original ratio of the number of ping pong balls in boxes A, B, C. 2. Three painters, all working at the same rate, paint 2/3 of a house in 6 hours. The following day only one painter returns. How many hours will the painter take to finish the job if he works at the same rate as before? 3. The Hubble constant, HO, is the ratio of recessional velocity of a galaxy to its distance. the Hubble constant is estimated to be 70km/sec per million parsecs of distance. (one parsec is equal to 3.26 light years.) Based on this ratio, how many billions of light years away would a galaxy be if it had a recessional velocity of 300,000 km/sec? Express your answer to the nearest whole number.

Asked By: Anthony W - 7/26/2007
question no. 1: the problem ends to a set of triple equations and triple unknown values. but the set has no real root... More
3A = 6/15 B/2 = 4/15 C + 40 = 5/15 Express B and C in terms of A: 6C + 240 = 15A, or C = 2.5A - 40 3B = 12A, or B = 4A so A + 4A + 2.5A - 40 = 260 ==> A = 40 then B = 160, and C = 60. so ratio is 2:8:3 1/3 house is done in 3 hours with three men so 9 hours to complete the last 1/3 with one man.
Answered By: John V - 7/26/2007

3A = 6/15 B/2 = 4/15 C + 40 = 5/15 Express B and C in terms of A: 6C + 240 = 15A, or C = 2.5A - 40 3B = 12A, or B = 4A so A + 4A + 2.5A - 40 = 260 ==> A = 40 then B = 160, and C = 60. so ratio is 2:8:3 1/3 house is done in 3 hours with three men so 9 hours to complete the last 1/3 with one man

Let box A have A balls, box B have B balls and box C have C balls whence we have... More

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